Base | Representation |
---|---|
bin | 10011000100000010001… |
… | …101000110001110111000 |
3 | 11122020100021220100211020 |
4 | 103010002031012032320 |
5 | 132430341003404422 |
6 | 2441450121302440 |
7 | 163434033246432 |
oct | 23040215061670 |
9 | 4566307810736 |
10 | 1310002013112 |
11 | 465628a91731 |
12 | 191a79034a20 |
13 | 966c033acb0 |
14 | 47593ab3652 |
15 | 2412207e95c |
hex | 131023463b8 |
1310002013112 has 64 divisors (see below), whose sum is σ = 3533127444000. Its totient is φ = 402369091584.
The previous prime is 1310002013107. The next prime is 1310002013129. The reversal of 1310002013112 is 2113102000131.
It is a happy number.
It is a super-2 number, since 2×13100020131122 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1310002013091 and 1310002013100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3512037 + ... + 3867092.
Almost surely, 21310002013112 is an apocalyptic number.
1310002013112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1310002013112 is an abundant number, since it is smaller than the sum of its proper divisors (2223125430888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310002013112 is a wasteful number, since it uses less digits than its factorization.
1310002013112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7379720 (or 7379716 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 1310002013112 its reverse (2113102000131), we get a palindrome (3423104013243).
The spelling of 1310002013112 in words is "one trillion, three hundred ten billion, two million, thirteen thousand, one hundred twelve".
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