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131001033031493 is a prime number
BaseRepresentation
bin11101110010010100001110…
…000010011111111101000101
3122011211120120020021011001112
4131302110032002133331011
5114132310103424001433
61142341013241534405
736410340502114232
oct3562241602377505
9564746506234045
10131001033031493
1138817253a57a59
1212838a64aa4405
135813462884961
14244c6ab8b0789
151022986868348
hex77250e09ff45

131001033031493 has 2 divisors, whose sum is σ = 131001033031494. Its totient is φ = 131001033031492.

The previous prime is 131001033031457. The next prime is 131001033031499. The reversal of 131001033031493 is 394130330100131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113943199638724 + 17057833392769 = 10674418^2 + 4130113^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131001033031493 is a prime.

It is a super-2 number, since 2×1310010330314932 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131001033031499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500516515746 + 65500516515747.

It is an arithmetic number, because the mean of its divisors is an integer number (65500516515747).

Almost surely, 2131001033031493 is an apocalyptic number.

It is an amenable number.

131001033031493 is a deficient number, since it is larger than the sum of its proper divisors (1).

131001033031493 is an equidigital number, since it uses as much as digits as its factorization.

131001033031493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8748, while the sum is 32.

The spelling of 131001033031493 in words is "one hundred thirty-one trillion, one billion, thirty-three million, thirty-one thousand, four hundred ninety-three".