13100110024110 has 16 divisors (see below), whose sum is σ = 31440264057936. Its totient is φ = 3493362673088.

The previous prime is 13100110024109. The next prime is 13100110024121. The reversal of 13100110024110 is 1142001100131.

It is a super-2 number, since 2×13100110024110² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 13100110024110.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 218335167039 + ... + 218335167098.

It is an arithmetic number, because the mean of its divisors is an integer number (1965016503621).

Almost surely, 2^{13100110024110} is an apocalyptic number.

13100110024110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13100110024110 is an abundant number, since it is smaller than the sum of its proper divisors (18340154033826).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100110024110 is a wasteful number, since it uses less digits than its factorization.

13100110024110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 436670334147.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 13100110024110 its reverse (1142001100131), we get a palindrome (14242111124241).

The spelling of 13100110024110 in words is "thirteen trillion, one hundred billion, one hundred ten million, twenty-four thousand, one hundred ten".