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131001110414320 = 2456128799324241
BaseRepresentation
bin11101110010010100010010…
…101001101100001111110000
3122011211120202121212121100011
4131302110102221230033300
5114132310233231224240
61142341025044304304
736410342431630156
oct3562242251541760
9564746677777304
10131001110414320
1138817293700903
1212838a869a2094
135813475909a03
14244c6b7c953d6
15102298d5516ea
hex772512a6c3f0

131001110414320 has 80 divisors (see below), whose sum is σ = 309678217182720. Its totient is φ = 51523512422400.

The previous prime is 131001110414287. The next prime is 131001110414333. The reversal of 131001110414320 is 23414011100131.

It is a tau number, because it is divible by the number of its divisors (80).

It is a super-2 number, since 2×1310011104143202 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131001110414291 and 131001110414300.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9387400 + ... + 18711640.

It is an arithmetic number, because the mean of its divisors is an integer number (3870977714784).

Almost surely, 2131001110414320 is an apocalyptic number.

131001110414320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131001110414320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (154839108591360).

131001110414320 is an abundant number, since it is smaller than the sum of its proper divisors (178677106768400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131001110414320 is a wasteful number, since it uses less digits than its factorization.

131001110414320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9327194 (or 9327188 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 131001110414320 its reverse (23414011100131), we get a palindrome (154415121514451).

The spelling of 131001110414320 in words is "one hundred thirty-one trillion, one billion, one hundred ten million, four hundred fourteen thousand, three hundred twenty".

Divisors: 1 2 4 5 8 10 16 20 40 61 80 122 244 305 488 610 976 1220 2440 2879 4880 5758 11516 14395 23032 28790 46064 57580 115160 175619 230320 351238 702476 878095 1404952 1756190 2809904 3512380 7024760 9324241 14049520 18648482 37296964 46621205 74593928 93242410 149187856 186484820 372969640 568778701 745939280 1137557402 2275114804 2843893505 4550229608 5687787010 9100459216 11375574020 22751148040 26844489839 45502296080 53688979678 107377959356 134222449195 214755918712 268444898390 429511837424 536889796780 1073779593560 1637513880179 2147559187120 3275027760358 6550055520716 8187569400895 13100111041432 16375138801790 26200222082864 32750277603580 65500555207160 131001110414320