1310011121310 has 32 divisors (see below), whose sum is σ = 3145178967840. Its totient is φ = 349208268288.

The previous prime is 1310011121267. The next prime is 1310011121351. The reversal of 1310011121310 is 131211100131.

It is a super-2 number, since 2×1310011121310² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 1310011121310.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7918687 + ... + 8082426.

It is an arithmetic number, because the mean of its divisors is an integer number (98286842745).

Almost surely, 2^{1310011121310} is an apocalyptic number.

1310011121310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1310011121310 is an abundant number, since it is smaller than the sum of its proper divisors (1835167846530).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310011121310 is a wasteful number, since it uses less digits than its factorization.

1310011121310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16003852.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 1310011121310 its reverse (131211100131), we get a palindrome (1441222221441).

The spelling of 1310011121310 in words is "one trillion, three hundred ten billion, eleven million, one hundred twenty-one thousand, three hundred ten".