131001341401040 has 160 divisors (see below), whose sum is σ = 357888611520000. Its totient is φ = 44080121756160.

The previous prime is 131001341401001. The next prime is 131001341401061. The reversal of 131001341401040 is 40104143100131.

It is a super-2 number, since 2×131001341401040² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131001341400997 and 131001341401015.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 90385790 + ... + 91823709.

It is an arithmetic number, because the mean of its divisors is an integer number (2236803822000).

Almost surely, 2^{131001341401040} is an apocalyptic number.

131001341401040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131001341401040 is an abundant number, since it is smaller than the sum of its proper divisors (226887270118960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131001341401040 is a wasteful number, since it uses less digits than its factorization.

131001341401040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 182209585 (or 182209579 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 131001341401040 its reverse (40104143100131), we get a palindrome (171105484501171).

The spelling of 131001341401040 in words is "one hundred thirty-one trillion, one billion, three hundred forty-one million, four hundred one thousand, forty".