1310013424140 has 48 divisors (see below), whose sum is σ = 3767173744992. Its totient is φ = 339895374336.

The previous prime is 1310013424127. The next prime is 1310013424141. The reversal of 1310013424140 is 414243100131.

It is a super-2 number, since 2×1310013424140² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1310013424140.

It is not an unprimeable number, because it can be changed into a prime (1310013424141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 295045849 + ... + 295050288.

It is an arithmetic number, because the mean of its divisors is an integer number (78482786354).

Almost surely, 2^{1310013424140} is an apocalyptic number.

1310013424140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1310013424140 is an abundant number, since it is smaller than the sum of its proper divisors (2457160320852).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310013424140 is a wasteful number, since it uses less digits than its factorization.

1310013424140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 590096186 (or 590096184 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 1310013424140 its reverse (414243100131), we get a palindrome (1724256524271).

The spelling of 1310013424140 in words is "one trillion, three hundred ten billion, thirteen million, four hundred twenty-four thousand, one hundred forty".