13100140231125 has 64 divisors (see below), whose sum is σ = 21905089300224. Its totient is φ = 6952686720000.

The previous prime is 13100140231093. The next prime is 13100140231133. The reversal of 13100140231125 is 52113204100131.

It is not a de Polignac number, because 13100140231125 - 2⁵ = 13100140231093 is a prime.

It is a super-2 number, since 2×13100140231125² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13100140231095 and 13100140231104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 80108694 + ... + 80272056.

It is an arithmetic number, because the mean of its divisors is an integer number (342267020316).

Almost surely, 2^{13100140231125} is an apocalyptic number.

13100140231125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

13100140231125 is a deficient number, since it is larger than the sum of its proper divisors (8804949069099).

13100140231125 is a wasteful number, since it uses less digits than its factorization.

13100140231125 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 164423 (or 164413 counting only the distinct ones).

The product of its (nonzero) digits is 720, while the sum is 24.

Adding to 13100140231125 its reverse (52113204100131), we get a palindrome (65213344331256).

The spelling of 13100140231125 in words is "thirteen trillion, one hundred billion, one hundred forty million, two hundred thirty-one thousand, one hundred twenty-five".