Base | Representation |
---|---|
bin | 111101000000001001… |
… | …0110110001100110100 |
3 | 110112010201022211022220 |
4 | 1322000102312030310 |
5 | 4121242332134444 |
6 | 140103051322340 |
7 | 12315223615416 |
oct | 1720022661464 |
9 | 415121284286 |
10 | 131001443124 |
11 | 50614999182 |
12 | 214801503b0 |
13 | c4794c8826 |
14 | 64aa4b09b6 |
15 | 361ac2c619 |
hex | 1e804b6334 |
131001443124 has 72 divisors (see below), whose sum is σ = 333011605248. Its totient is φ = 40034355840.
The previous prime is 131001443057. The next prime is 131001443149. The reversal of 131001443124 is 421344100131.
It is a super-2 number, since 2×1310014431242 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131001443094 and 131001443103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 353457 + ... + 622040.
It is an arithmetic number, because the mean of its divisors is an integer number (4625161184).
Almost surely, 2131001443124 is an apocalyptic number.
It is an amenable number.
131001443124 is an abundant number, since it is smaller than the sum of its proper divisors (202010162124).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131001443124 is a wasteful number, since it uses less digits than its factorization.
131001443124 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 975573 (or 975552 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 131001443124 its reverse (421344100131), we get a palindrome (552345543255).
The spelling of 131001443124 in words is "one hundred thirty-one billion, one million, four hundred forty-three thousand, one hundred twenty-four".
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