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13100201102320 = 245616194336781
BaseRepresentation
bin1011111010100010000011…
…0101010100101111110000
31201101100220112112221001021
42332220200311110233300
53204113202440233240
643510052125545224
72521313124045133
oct276504065245760
951340815487037
1013100201102320
1141a0845000a62
121576aa6a15214
13740461049ac7
143340a5a7421a
1517ab7639754a
hexbea20d54bf0

13100201102320 has 80 divisors (see below), whose sum is σ = 31007297414880. Its totient is φ = 5145849676800.

The previous prime is 13100201102299. The next prime is 13100201102353. The reversal of 13100201102320 is 2320110200131.

13100201102320 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (80).

It is a super-2 number, since 2×131002011023202 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a junction number, because it is equal to n+sod(n) for n = 13100201102294 and 13100201102303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 852330 + ... + 5189110.

It is an arithmetic number, because the mean of its divisors is an integer number (387591217686).

Almost surely, 213100201102320 is an apocalyptic number.

13100201102320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13100201102320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15503648707440).

13100201102320 is an abundant number, since it is smaller than the sum of its proper divisors (17907096312560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100201102320 is a wasteful number, since it uses less digits than its factorization.

13100201102320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4337474 (or 4337468 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13100201102320 its reverse (2320110200131), we get a palindrome (15420311302451).

The spelling of 13100201102320 in words is "thirteen trillion, one hundred billion, two hundred one million, one hundred two thousand, three hundred twenty".

Divisors: 1 2 4 5 8 10 16 20 40 61 80 122 244 305 488 610 619 976 1220 1238 2440 2476 3095 4880 4952 6190 9904 12380 24760 37759 49520 75518 151036 188795 302072 377590 604144 755180 1510360 3020720 4336781 8673562 17347124 21683905 34694248 43367810 69388496 86735620 173471240 264543641 346942480 529087282 1058174564 1322718205 2116349128 2645436410 2684467439 4232698256 5290872820 5368934878 10581745640 10737869756 13422337195 21163491280 21475739512 26844674390 42951479024 53689348780 107378697560 163752513779 214757395120 327505027558 655010055116 818762568895 1310020110232 1637525137790 2620040220464 3275050275580 6550100551160 13100201102320