Base | Representation |
---|---|
bin | 1011111010100010000011… |
… | …0101010100101111110000 |
3 | 1201101100220112112221001021 |
4 | 2332220200311110233300 |
5 | 3204113202440233240 |
6 | 43510052125545224 |
7 | 2521313124045133 |
oct | 276504065245760 |
9 | 51340815487037 |
10 | 13100201102320 |
11 | 41a0845000a62 |
12 | 1576aa6a15214 |
13 | 740461049ac7 |
14 | 3340a5a7421a |
15 | 17ab7639754a |
hex | bea20d54bf0 |
13100201102320 has 80 divisors (see below), whose sum is σ = 31007297414880. Its totient is φ = 5145849676800.
The previous prime is 13100201102299. The next prime is 13100201102353. The reversal of 13100201102320 is 2320110200131.
13100201102320 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (80).
It is a super-2 number, since 2×131002011023202 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a junction number, because it is equal to n+sod(n) for n = 13100201102294 and 13100201102303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 852330 + ... + 5189110.
It is an arithmetic number, because the mean of its divisors is an integer number (387591217686).
Almost surely, 213100201102320 is an apocalyptic number.
13100201102320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13100201102320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15503648707440).
13100201102320 is an abundant number, since it is smaller than the sum of its proper divisors (17907096312560).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100201102320 is a wasteful number, since it uses less digits than its factorization.
13100201102320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4337474 (or 4337468 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 13100201102320 its reverse (2320110200131), we get a palindrome (15420311302451).
The spelling of 13100201102320 in words is "thirteen trillion, one hundred billion, two hundred one million, one hundred two thousand, three hundred twenty".
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