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131002131300 = 2235216722711519
BaseRepresentation
bin111101000000001010…
…1011110001101100100
3110112010202121210022220
41322000111132031210
54121243021200200
6140103114152340
712315232512645
oct1720025361544
9415122553286
10131002131300
1150615319217
12214804226b0
13c4796a9b31
1464aa60d6cc
15361ad164a0
hex1e8055e364

131002131300 has 144 divisors (see below), whose sum is σ = 383015485440. Its totient is φ = 34568743040.

The previous prime is 131002131289. The next prime is 131002131301. The reversal of 131002131300 is 3131200131.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 131002131300.

It is not an unprimeable number, because it can be changed into a prime (131002131301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 11366941 + ... + 11378459.

It is an arithmetic number, because the mean of its divisors is an integer number (2659829760).

Almost surely, 2131002131300 is an apocalyptic number.

131002131300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131002131300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (191507742720).

131002131300 is an abundant number, since it is smaller than the sum of its proper divisors (252013354140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131002131300 is a wasteful number, since it uses less digits than its factorization.

131002131300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11930 (or 11923 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 131002131300 its reverse (3131200131), we get a palindrome (134133331431).

The spelling of 131002131300 in words is "one hundred thirty-one billion, two million, one hundred thirty-one thousand, three hundred".

Divisors: 1 2 3 4 5 6 10 12 15 20 25 30 50 60 75 100 150 167 227 300 334 454 501 668 681 835 908 1002 1135 1362 1670 2004 2270 2505 2724 3340 3405 4175 4540 5010 5675 6810 8350 10020 11350 11519 12525 13620 16700 17025 22700 23038 25050 34050 34557 37909 46076 50100 57595 68100 69114 75818 113727 115190 138228 151636 172785 189545 227454 230380 287975 345570 379090 454908 568635 575950 691140 758180 863925 947725 1137270 1151900 1727850 1895450 1923673 2274540 2614813 2843175 3455700 3790900 3847346 5229626 5686350 5771019 7694692 7844439 9618365 10459252 11372700 11542038 13074065 15688878 19236730 23084076 26148130 28855095 31377756 38473460 39222195 48091825 52296260 57710190 65370325 78444390 96183650 115420380 130740650 144275475 156888780 192367300 196110975 261481300 288550950 392221950 436673771 577101900 784443900 873347542 1310021313 1746695084 2183368855 2620042626 4366737710 5240085252 6550106565 8733475420 10916844275 13100213130 21833688550 26200426260 32750532825 43667377100 65501065650 131002131300