Base | Representation |
---|---|
bin | 1011111010100010110010… |
… | …1101001101001111110000 |
3 | 1201101101102102101021022122 |
4 | 2332220230231031033300 |
5 | 3204114104434113130 |
6 | 43510124003253412 |
7 | 2521321063154333 |
oct | 276505455151760 |
9 | 51341372337278 |
10 | 13100400301040 |
11 | 41a09374969a8 |
12 | 1576b4167a268 |
13 | 7404933b3480 |
14 | 3340c42c861a |
15 | 17ab88ae42e5 |
hex | bea2cb4d3f0 |
13100400301040 has 40 divisors (see below), whose sum is σ = 32801386910208. Its totient is φ = 4837070880000.
The previous prime is 13100400301013. The next prime is 13100400301061. The reversal of 13100400301040 is 4010300400131.
It is a tau number, because it is divible by the number of its divisors (40).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6298268336 + ... + 6298270415.
Almost surely, 213100400301040 is an apocalyptic number.
13100400301040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13100400301040 is an abundant number, since it is smaller than the sum of its proper divisors (19700986609168).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100400301040 is a wasteful number, since it uses less digits than its factorization.
13100400301040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12596538777 (or 12596538771 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 13100400301040 its reverse (4010300400131), we get a palindrome (17110700701171).
Subtracting from 13100400301040 its reverse (4010300400131), we obtain a palindrome (9090099900909).
The spelling of 13100400301040 in words is "thirteen trillion, one hundred billion, four hundred million, three hundred one thousand, forty".
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