Base | Representation |
---|---|
bin | 11101110010011100111101… |
… | …000101010110000001111100 |
3 | 122011212110202212220100202011 |
4 | 131302130331011112001330 |
5 | 114132433311013203040 |
6 | 1142345204050541004 |
7 | 36411122101066354 |
oct | 3562347505260174 |
9 | 564773685810664 |
10 | 131010412241020 |
11 | 38820227303994 |
12 | 1283a841b97764 |
13 | 58142c8a77390 |
14 | 244cd1b3d7b64 |
15 | 1022d34e9d3ea |
hex | 77273d15607c |
131010412241020 has 96 divisors (see below), whose sum is σ = 304394322960000. Its totient is φ = 47049990718464.
The previous prime is 131010412241011. The next prime is 131010412241089. The reversal of 131010412241020 is 20142214010131.
It is a junction number, because it is equal to n+sod(n) for n = 131010412240982 and 131010412241000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 26579866 + ... + 31120894.
It is an arithmetic number, because the mean of its divisors is an integer number (3170774197500).
Almost surely, 2131010412241020 is an apocalyptic number.
131010412241020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131010412241020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (152197161480000).
131010412241020 is an abundant number, since it is smaller than the sum of its proper divisors (173383910718980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131010412241020 is a wasteful number, since it uses less digits than its factorization.
131010412241020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4544087 (or 4544085 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 131010412241020 its reverse (20142214010131), we get a palindrome (151152626251151).
The spelling of 131010412241020 in words is "one hundred thirty-one trillion, ten billion, four hundred twelve million, two hundred forty-one thousand, twenty".
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