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131011102113120 = 25325537012448791
BaseRepresentation
bin11101110010011101100110…
…001100111111110101100000
3122011212112112222000111100200
4131302131212030333311200
5114132441214120104440
61142345400333145200
736411145145646315
oct3562354614776540
9564775488014320
10131011102113120
1138820550766019
121283a9b502b200
1358143a897b918
14244cd84c96d0c
151022d7581ec30
hex77276633fd60

131011102113120 has 288 divisors, whose sum is σ = 456160758266304. Its totient is φ = 34228207104000.

The previous prime is 131011102113107. The next prime is 131011102113187. The reversal of 131011102113120 is 21311201110131.

131011102113120 is a `hidden beast` number, since 1 + 31 + 0 + 1 + 110 + 211 + 312 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (288).

It is a super-2 number, since 2×1310111021131202 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 131011102113093 and 131011102113102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 52275925 + ... + 54724715.

It is an arithmetic number, because the mean of its divisors is an integer number (1583891521758).

Almost surely, 2131011102113120 is an apocalyptic number.

131011102113120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131011102113120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (228080379133152).

131011102113120 is an abundant number, since it is smaller than the sum of its proper divisors (325149656153184).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131011102113120 is a wasteful number, since it uses less digits than its factorization.

131011102113120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2449566 (or 2449555 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 18.

Adding to 131011102113120 its reverse (21311201110131), we get a palindrome (152322303223251).

The spelling of 131011102113120 in words is "one hundred thirty-one trillion, eleven billion, one hundred two million, one hundred thirteen thousand, one hundred twenty".