Base | Representation |
---|---|
bin | 1011111010100101011100… |
… | …0100110001100101111100 |
3 | 1201101110020221220201202222 |
4 | 2332221113010301211330 |
5 | 3204122033421403200 |
6 | 43510322314504512 |
7 | 2521344514065455 |
oct | 276512704614574 |
9 | 51343227821688 |
10 | 13101111122300 |
11 | 41a1171757493 |
12 | 15770bb735138 |
13 | 740577741176 |
14 | 33415087c12c |
15 | 17abcb202d85 |
hex | bea5713197c |
13101111122300 has 18 divisors (see below), whose sum is σ = 28429411135608. Its totient is φ = 5240444448880.
The previous prime is 13101111122269. The next prime is 13101111122321. The reversal of 13101111122300 is 322111110131.
It is a super-2 number, since 2×131011111223002 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 65505555512 + ... + 65505555711.
It is an arithmetic number, because the mean of its divisors is an integer number (1579411729756).
Almost surely, 213101111122300 is an apocalyptic number.
13101111122300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13101111122300 is an abundant number, since it is smaller than the sum of its proper divisors (15328300013308).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13101111122300 is a wasteful number, since it uses less digits than its factorization.
13101111122300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 131011111237 (or 131011111230 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 13101111122300 its reverse (322111110131), we get a palindrome (13423222232431).
The spelling of 13101111122300 in words is "thirteen trillion, one hundred one billion, one hundred eleven million, one hundred twenty-two thousand, three hundred".
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