Base | Representation |
---|---|
bin | 11101110010011101100110… |
… | …111011100000001011010010 |
3 | 122011212112120210221212101112 |
4 | 131302131212323200023102 |
5 | 114132441230230213320 |
6 | 1142345401450333322 |
7 | 36411145354403000 |
oct | 3562354673401322 |
9 | 564775523855345 |
10 | 131011114304210 |
11 | 388205576323a8 |
12 | 1283a9b912a242 |
13 | 58143ab35989a |
14 | 244cd8674ba70 |
15 | 1022d7692bec5 |
hex | 772766ee02d2 |
131011114304210 has 96 divisors (see below), whose sum is σ = 281879894332800. Its totient is φ = 43822531079040.
The previous prime is 131011114304209. The next prime is 131011114304219. The reversal of 131011114304210 is 12403411110131.
It is not an unprimeable number, because it can be changed into a prime (131011114304219) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5595164 + ... + 17126823.
It is an arithmetic number, because the mean of its divisors is an integer number (2936248899300).
Almost surely, 2131011114304210 is an apocalyptic number.
131011114304210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131011114304210 is an abundant number, since it is smaller than the sum of its proper divisors (150868780028590).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131011114304210 is an equidigital number, since it uses as much as digits as its factorization.
131011114304210 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22722097 (or 22722042 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 23.
Adding to 131011114304210 its reverse (12403411110131), we get a palindrome (143414525414341).
The spelling of 131011114304210 in words is "one hundred thirty-one trillion, eleven billion, one hundred fourteen million, three hundred four thousand, two hundred ten".
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