Base | Representation |
---|---|
bin | 11101110010011101101000… |
… | …100010001000111111111111 |
3 | 122011212112122200120211100101 |
4 | 131302131220202020333333 |
5 | 114132441304122210421 |
6 | 1142345404251141531 |
7 | 36411146132163601 |
oct | 3562355042107777 |
9 | 564775580524311 |
10 | 131011141210111 |
11 | 3882057083a188 |
12 | 1283aa061448a7 |
13 | 58143b3aba436 |
14 | 244cd8a153171 |
15 | 1022d78e94191 |
hex | 772768888fff |
131011141210111 has 2 divisors, whose sum is σ = 131011141210112. Its totient is φ = 131011141210110.
The previous prime is 131011141210109. The next prime is 131011141210121. The reversal of 131011141210111 is 111012141110131.
It is a weak prime.
It is an emirp because it is prime and its reverse (111012141110131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131011141210111 - 21 = 131011141210109 is a prime.
Together with 131011141210109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131011141210121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505570605055 + 65505570605056.
It is an arithmetic number, because the mean of its divisors is an integer number (65505570605056).
Almost surely, 2131011141210111 is an apocalyptic number.
131011141210111 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011141210111 is an equidigital number, since it uses as much as digits as its factorization.
131011141210111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 19.
Adding to 131011141210111 its reverse (111012141110131), we get a palindrome (242023282320242).
The spelling of 131011141210111 in words is "one hundred thirty-one trillion, eleven billion, one hundred forty-one million, two hundred ten thousand, one hundred eleven".
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