Base | Representation |
---|---|
bin | 10011000100001000110… |
… | …101101101100011010111 |
3 | 11122020122001100111120221 |
4 | 103010020311231203113 |
5 | 132431103002320343 |
6 | 2441505135135211 |
7 | 163436554335625 |
oct | 23041065554327 |
9 | 4566561314527 |
10 | 1310113323223 |
11 | 4656858a8661 |
12 | 191aaa374507 |
13 | 9670a411773 |
14 | 475a47aa515 |
15 | 2412bc1a5ed |
hex | 13108d6d8d7 |
1310113323223 has 2 divisors, whose sum is σ = 1310113323224. Its totient is φ = 1310113323222.
The previous prime is 1310113323221. The next prime is 1310113323247. The reversal of 1310113323223 is 3223233110131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310113323223 - 21 = 1310113323221 is a prime.
It is a super-2 number, since 2×13101133232232 (a number of 25 digits) contains 22 as substring.
Together with 1310113323221, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310113323221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655056661611 + 655056661612.
It is an arithmetic number, because the mean of its divisors is an integer number (655056661612).
Almost surely, 21310113323223 is an apocalyptic number.
1310113323223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310113323223 is an equidigital number, since it uses as much as digits as its factorization.
1310113323223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1310113323223 its reverse (3223233110131), we get a palindrome (4533346433354).
The spelling of 1310113323223 in words is "one trillion, three hundred ten billion, one hundred thirteen million, three hundred twenty-three thousand, two hundred twenty-three".
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