Base | Representation |
---|---|
bin | 111101000000011101… |
… | …1000101011111001111 |
3 | 110112011110011201222121 |
4 | 1322000323011133033 |
5 | 4121303032212003 |
6 | 140104105353411 |
7 | 12315412360621 |
oct | 1720073053717 |
9 | 415143151877 |
10 | 131011991503 |
11 | 5061a943348 |
12 | 21483798867 |
13 | c47b74cb83 |
14 | 64aba58c11 |
15 | 361bb12cbd |
hex | 1e80ec57cf |
131011991503 has 2 divisors, whose sum is σ = 131011991504. Its totient is φ = 131011991502.
The previous prime is 131011991501. The next prime is 131011991527. The reversal of 131011991503 is 305199110131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131011991503 - 21 = 131011991501 is a prime.
Together with 131011991501, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131011991501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505995751 + 65505995752.
It is an arithmetic number, because the mean of its divisors is an integer number (65505995752).
Almost surely, 2131011991503 is an apocalyptic number.
131011991503 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011991503 is an equidigital number, since it uses as much as digits as its factorization.
131011991503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3645, while the sum is 34.
The spelling of 131011991503 in words is "one hundred thirty-one billion, eleven million, nine hundred ninety-one thousand, five hundred three".
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