Base | Representation |
---|---|
bin | 11101110010011110101001… |
… | …000101011011010110001101 |
3 | 122011212122110011102112002201 |
4 | 131302132221011123112031 |
5 | 114133001013343432000 |
6 | 1142350103535321501 |
7 | 36411215022361660 |
oct | 3562365105332615 |
9 | 564778404375081 |
10 | 131012224202125 |
11 | 38820a77098102 |
12 | 1283b068980291 |
13 | 5814527294806 |
14 | 244d04dd056d7 |
15 | 1022dde0ba96a |
hex | 7727a915b58d |
131012224202125 has 48 divisors (see below), whose sum is σ = 189691463969280. Its totient is φ = 88496101029600.
The previous prime is 131012224202099. The next prime is 131012224202147. The reversal of 131012224202125 is 521202422210131.
It is not a de Polignac number, because 131012224202125 - 27 = 131012224201997 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131012224202093 and 131012224202102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 12749365 + ... + 20605114.
It is an arithmetic number, because the mean of its divisors is an integer number (3951905499360).
Almost surely, 2131012224202125 is an apocalyptic number.
It is an amenable number.
131012224202125 is a deficient number, since it is larger than the sum of its proper divisors (58679239767155).
131012224202125 is an frugal number, since it uses more digits than its factorization.
131012224202125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33354635 (or 33354558 counting only the distinct ones).
The product of its (nonzero) digits is 3840, while the sum is 28.
Adding to 131012224202125 its reverse (521202422210131), we get a palindrome (652214646412256).
The spelling of 131012224202125 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, two hundred two thousand, one hundred twenty-five".
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