1310131020181 has 2 divisors, whose sum is σ = 1310131020182. Its totient is φ = 1310131020180.

The previous prime is 1310131020179. The next prime is 1310131020203. The reversal of 1310131020181 is 1810201310131.

It is an a-pointer prime, because the next prime (1310131020203) can be obtained adding 1310131020181 to its sum of digits (22).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1300817805156 + 9313215025 = 1140534^2 + 96505^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310131020181 - 2¹ = 1310131020179 is a prime.

It is a super-2 number, since 2×1310131020181² (a number of 25 digits) contains 22 as substring.

Together with 1310131020179, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310131020881) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655065510090 + 655065510091.

It is an arithmetic number, because the mean of its divisors is an integer number (655065510091).

Almost surely, 2^{1310131020181} is an apocalyptic number.

It is an amenable number.

1310131020181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310131020181 is an equidigital number, since it uses as much as digits as its factorization.

1310131020181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 22.

The spelling of 1310131020181 in words is "one trillion, three hundred ten billion, one hundred thirty-one million, twenty thousand, one hundred eighty-one".