Base | Representation |
---|---|
bin | 1011111010100110001110… |
… | …0101111001010011000000 |
3 | 1201101110210121002021211101 |
4 | 2332221203211321103000 |
5 | 3204123001202144300 |
6 | 43510355220024144 |
7 | 2521352644120351 |
oct | 276514345712300 |
9 | 51343717067741 |
10 | 13101321131200 |
11 | 41a126a256265 |
12 | 1577159b32054 |
13 | 7405ac0c10a3 |
14 | 334170707d28 |
15 | 17abde887b6a |
hex | bea639794c0 |
13101321131200 has 84 divisors (see below), whose sum is σ = 32257580429592. Its totient is φ = 5237254144000.
The previous prime is 13101321131159. The next prime is 13101321131209. The reversal of 13101321131200 is 213112310131.
13101321131200 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×131013211312002 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13101321131209) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4347 + ... + 5118853.
It is an arithmetic number, because the mean of its divisors is an integer number (384018814638).
Almost surely, 213101321131200 is an apocalyptic number.
13101321131200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13101321131200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16128790214796).
13101321131200 is an abundant number, since it is smaller than the sum of its proper divisors (19156259298392).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13101321131200 is a wasteful number, since it uses less digits than its factorization.
13101321131200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5116130 (or 5116115 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 13101321131200 its reverse (213112310131), we get a palindrome (13314433441331).
The spelling of 13101321131200 in words is "thirteen trillion, one hundred one billion, three hundred twenty-one million, one hundred thirty-one thousand, two hundred".
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