Base | Representation |
---|---|
bin | 1011111010101000111000… |
… | …0010101001111000010100 |
3 | 1201101112122020011220000012 |
4 | 2332222032002221320110 |
5 | 3204130431012011200 |
6 | 43510554020335352 |
7 | 2521406412430121 |
oct | 276521602517024 |
9 | 51345566156005 |
10 | 13102033313300 |
11 | 41a15a5266208 |
12 | 1577318544558 |
13 | 740693807309 |
14 | 3341db133748 |
15 | 17ac32164a35 |
hex | bea8e0a9e14 |
13102033313300 has 36 divisors (see below), whose sum is σ = 29927802414720. Its totient is φ = 4964981044320.
The previous prime is 13102033313261. The next prime is 13102033313309. The reversal of 13102033313300 is 331333020131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13102033313309) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3447901604 + ... + 3447905403.
Almost surely, 213102033313300 is an apocalyptic number.
13102033313300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13102033313300 is an abundant number, since it is smaller than the sum of its proper divisors (16825769101420).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13102033313300 is a wasteful number, since it uses less digits than its factorization.
13102033313300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6895807040 (or 6895807033 counting only the distinct ones).
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 13102033313300 its reverse (331333020131), we get a palindrome (13433366333431).
The spelling of 13102033313300 in words is "thirteen trillion, one hundred two billion, thirty-three million, three hundred thirteen thousand, three hundred".
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