Base | Representation |
---|---|
bin | 11000011001111000… |
… | …10111111111110101 |
3 | 1020211002211101011121 |
4 | 30030330113333311 |
5 | 203313111233123 |
6 | 10004034303541 |
7 | 642452430166 |
oct | 141474277765 |
9 | 36732741147 |
10 | 13102055413 |
11 | 5613850177 |
12 | 2657a27bb1 |
13 | 130a584c15 |
14 | 8c413376d |
15 | 51a3b075d |
hex | 30cf17ff5 |
13102055413 has 2 divisors, whose sum is σ = 13102055414. Its totient is φ = 13102055412.
The previous prime is 13102055399. The next prime is 13102055441. The reversal of 13102055413 is 31455020131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8952376689 + 4149678724 = 94617^2 + 64418^2 .
It is a cyclic number.
It is not a de Polignac number, because 13102055413 - 25 = 13102055381 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13102055443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551027706 + 6551027707.
It is an arithmetic number, because the mean of its divisors is an integer number (6551027707).
Almost surely, 213102055413 is an apocalyptic number.
It is an amenable number.
13102055413 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102055413 is an equidigital number, since it uses as much as digits as its factorization.
13102055413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 13102055413 its reverse (31455020131), we get a palindrome (44557075544).
The spelling of 13102055413 in words is "thirteen billion, one hundred two million, fifty-five thousand, four hundred thirteen".
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