Base | Representation |
---|---|
bin | 11101110010100111000001… |
… | …111001011000101000111100 |
3 | 122011220111200211012022010110 |
4 | 131302213001321120220330 |
5 | 114133122434441112200 |
6 | 1142354153341510020 |
7 | 36411654142030446 |
oct | 3562470171305074 |
9 | 564814624168113 |
10 | 131021230410300 |
11 | 3882487893965a |
12 | 12840960b72310 |
13 | 5815331109789 |
14 | 244d666095496 |
15 | 1023269ac1b50 |
hex | 7729c1e58a3c |
131021230410300 has 36 divisors (see below), whose sum is σ = 379088093321336. Its totient is φ = 34938994776000.
The previous prime is 131021230410289. The next prime is 131021230410347. The reversal of 131021230410300 is 3014032120131.
131021230410300 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 218368717051 + ... + 218368717650.
Almost surely, 2131021230410300 is an apocalyptic number.
131021230410300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131021230410300 is an abundant number, since it is smaller than the sum of its proper divisors (248066862911036).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131021230410300 is a wasteful number, since it uses less digits than its factorization.
131021230410300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 436737434718 (or 436737434711 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 131021230410300 its reverse (3014032120131), we get a palindrome (134035262530431).
The spelling of 131021230410300 in words is "one hundred thirty-one trillion, twenty-one billion, two hundred thirty million, four hundred ten thousand, three hundred".
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