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13102129973 is a prime number
BaseRepresentation
bin11000011001111001…
…01010001100110101
31020211002222011110002
430030330222030311
5203313121124343
610004040041045
7642453160442
oct141474521465
936732864402
1013102129973
1156138a1199
122657a63185
13130a5acb3a
148c41529c9
1551a3c78b8
hex30cf2a335

13102129973 has 2 divisors, whose sum is σ = 13102129974. Its totient is φ = 13102129972.

The previous prime is 13102129967. The next prime is 13102129979. The reversal of 13102129973 is 37992120131.

13102129973 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (13102129967) and next prime (13102129979).

It can be written as a sum of positive squares in only one way, i.e., 9756895729 + 3345234244 = 98777^2 + 57838^2 .

It is a cyclic number.

It is not a de Polignac number, because 13102129973 - 214 = 13102113589 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13102129979) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551064986 + 6551064987.

It is an arithmetic number, because the mean of its divisors is an integer number (6551064987).

Almost surely, 213102129973 is an apocalyptic number.

It is an amenable number.

13102129973 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102129973 is an equidigital number, since it uses as much as digits as its factorization.

13102129973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20412, while the sum is 38.

The spelling of 13102129973 in words is "thirteen billion, one hundred two million, one hundred twenty-nine thousand, nine hundred seventy-three".