Base | Representation |
---|---|
bin | 1011111010101001111111… |
… | …1010101011011010001100 |
3 | 1201101120102010111100002120 |
4 | 2332222133322223122030 |
5 | 3204132034300243200 |
6 | 43511043452252540 |
7 | 2521420013506203 |
oct | 276523772533214 |
9 | 51346363440076 |
10 | 13102333212300 |
11 | 41a1739580822 |
12 | 15773a0a71150 |
13 | 74071099b147 |
14 | 334228cbc23a |
15 | 17ac4d6539a0 |
hex | bea9feab68c |
13102333212300 has 36 divisors (see below), whose sum is σ = 37909417428456. Its totient is φ = 3493955523200.
The previous prime is 13102333212289. The next prime is 13102333212383. The reversal of 13102333212300 is 321233320131.
It is a super-2 number, since 2×131023332123002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 21837221721 + ... + 21837222320.
Almost surely, 213102333212300 is an apocalyptic number.
13102333212300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13102333212300 is an abundant number, since it is smaller than the sum of its proper divisors (24807084216156).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13102333212300 is a wasteful number, since it uses less digits than its factorization.
13102333212300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43674444058 (or 43674444051 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 13102333212300 its reverse (321233320131), we get a palindrome (13423566532431).
The spelling of 13102333212300 in words is "thirteen trillion, one hundred two billion, three hundred thirty-three million, two hundred twelve thousand, three hundred".
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