Base | Representation |
---|---|
bin | 1011111010101100111001… |
… | …0010100011011111000000 |
3 | 1201101122102100110101110021 |
4 | 2332223032102203133000 |
5 | 3204140132433120412 |
6 | 43511253003543224 |
7 | 2521445211500512 |
oct | 276531622433700 |
9 | 51348370411407 |
10 | 13103111223232 |
11 | 41a1aa8762968 |
12 | 157757952ab14 |
13 | 740805c22444 |
14 | 3342a0361bb2 |
15 | 17ac96ad5607 |
hex | beace4a37c0 |
13103111223232 has 14 divisors (see below), whose sum is σ = 26001486333728. Its totient is φ = 6551555611584.
The previous prime is 13103111223211. The next prime is 13103111223263. The reversal of 13103111223232 is 23232211130131.
It is a junction number, because it is equal to n+sod(n) for n = 13103111223197 and 13103111223206.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102368056368 + ... + 102368056495.
Almost surely, 213103111223232 is an apocalyptic number.
It is an amenable number.
13103111223232 is a deficient number, since it is larger than the sum of its proper divisors (12898375110496).
13103111223232 is an equidigital number, since it uses as much as digits as its factorization.
13103111223232 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 204736112875 (or 204736112865 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13103111223232 its reverse (23232211130131), we get a palindrome (36335322353363).
The spelling of 13103111223232 in words is "thirteen trillion, one hundred three billion, one hundred eleven million, two hundred twenty-three thousand, two hundred thirty-two".
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