Base | Representation |
---|---|
bin | 111101000001000010… |
… | …0110000001110111100 |
3 | 110112012210111212111221 |
4 | 1322002010300032330 |
5 | 4121323003144400 |
6 | 140110035323124 |
7 | 12316035461635 |
oct | 1720204601674 |
9 | 415183455457 |
10 | 131031303100 |
11 | 5062a833445 |
12 | 2148a1504a4 |
13 | c482751b59 |
14 | 64b044488c |
15 | 361d679c1a |
hex | 1e821303bc |
131031303100 has 54 divisors (see below), whose sum is σ = 284865257040. Its totient is φ = 52315449120.
The previous prime is 131031303079. The next prime is 131031303107. The reversal of 131031303100 is 1303130131.
It is a super-2 number, since 2×1310313031002 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131031303107) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 116679139 + ... + 116680261.
Almost surely, 2131031303100 is an apocalyptic number.
131031303100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131031303100 is an abundant number, since it is smaller than the sum of its proper divisors (153833953940).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131031303100 is a wasteful number, since it uses less digits than its factorization.
131031303100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3299 (or 2169 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 131031303100 its reverse (1303130131), we get a palindrome (132334433231).
The spelling of 131031303100 in words is "one hundred thirty-one billion, thirty-one million, three hundred three thousand, one hundred".
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