Base | Representation |
---|---|
bin | 1011111010101101111111… |
… | …1001001001100110110000 |
3 | 1201101200011221011201110002 |
4 | 2332223133321021212300 |
5 | 3204141234034203040 |
6 | 43511342153525132 |
7 | 2521455425660663 |
oct | 276533771114660 |
9 | 51350157151402 |
10 | 13103406553520 |
11 | 41a213a437988 |
12 | 15776404137a8 |
13 | 7408521768aa |
14 | 3342cb67b6da |
15 | 17acb29c0a15 |
hex | beadfe499b0 |
13103406553520 has 40 divisors (see below), whose sum is σ = 30527977658784. Its totient is φ = 5230600054272.
The previous prime is 13103406553487. The next prime is 13103406553529. The reversal of 13103406553520 is 2535560430131.
It is a tau number, because it is divible by the number of its divisors (40).
It is not an unprimeable number, because it can be changed into a prime (13103406553529) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 168125909 + ... + 168203828.
Almost surely, 213103406553520 is an apocalyptic number.
13103406553520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13103406553520 is an abundant number, since it is smaller than the sum of its proper divisors (17424571105264).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13103406553520 is a wasteful number, since it uses less digits than its factorization.
13103406553520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 336330237 (or 336330231 counting only the distinct ones).
The product of its (nonzero) digits is 162000, while the sum is 38.
Adding to 13103406553520 its reverse (2535560430131), we get a palindrome (15638966983651).
The spelling of 13103406553520 in words is "thirteen trillion, one hundred three billion, four hundred six million, five hundred fifty-three thousand, five hundred twenty".
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