Base | Representation |
---|---|
bin | 11101110010111000101001… |
… | …000111011000010000111110 |
3 | 122011222022111210200122210120 |
4 | 131302320221013120100332 |
5 | 114133430202323014324 |
6 | 1142411002110515410 |
7 | 36413223606635145 |
oct | 3562705107302076 |
9 | 564868453618716 |
10 | 131040142001214 |
11 | 388318a2a4a836 |
12 | 1284455a505b66 |
13 | 5817056161464 |
14 | 245053b9b875c |
15 | 10239c4ee6179 |
hex | 772e291d843e |
131040142001214 has 32 divisors (see below), whose sum is σ = 265773713262336. Its totient is φ = 43064485779840.
The previous prime is 131040142001213. The next prime is 131040142001239. The reversal of 131040142001214 is 412100241040131.
It is a happy number.
131040142001214 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131040142001213) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 54169489 + ... + 56536835.
It is an arithmetic number, because the mean of its divisors is an integer number (8305428539448).
Almost surely, 2131040142001214 is an apocalyptic number.
131040142001214 is an abundant number, since it is smaller than the sum of its proper divisors (134733571261122).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131040142001214 is a wasteful number, since it uses less digits than its factorization.
131040142001214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2497360.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 131040142001214 its reverse (412100241040131), we get a palindrome (543140383041345).
The spelling of 131040142001214 in words is "one hundred thirty-one trillion, forty billion, one hundred forty-two million, one thousand, two hundred fourteen".
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