Base | Representation |
---|---|
bin | 1011111010110000100101… |
… | …0011110010101001100000 |
3 | 1201101201222100122202001121 |
4 | 2332230021103302221200 |
5 | 3204144144424400412 |
6 | 43511535134542024 |
7 | 2521511564051620 |
oct | 276541123625140 |
9 | 51351870582047 |
10 | 13104101403232 |
11 | 41a2466689844 |
12 | 15777b5067914 |
13 | 740933101978 |
14 | 334355a74880 |
15 | 17ad039c7107 |
hex | beb094f2a60 |
13104101403232 has 48 divisors (see below), whose sum is σ = 29490460044192. Its totient is φ = 5614856432640.
The previous prime is 13104101403229. The next prime is 13104101403269. The reversal of 13104101403232 is 23230410140131.
It is a junction number, because it is equal to n+sod(n) for n = 13104101403197 and 13104101403206.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5119869 + ... + 7240252.
It is an arithmetic number, because the mean of its divisors is an integer number (614384584254).
Almost surely, 213104101403232 is an apocalyptic number.
It is an amenable number.
13104101403232 is an abundant number, since it is smaller than the sum of its proper divisors (16386358640960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13104101403232 is a wasteful number, since it uses less digits than its factorization.
13104101403232 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12364871 (or 12364863 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13104101403232 its reverse (23230410140131), we get a palindrome (36334511543363).
The spelling of 13104101403232 in words is "thirteen trillion, one hundred four billion, one hundred one million, four hundred three thousand, two hundred thirty-two".
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