Base | Representation |
---|---|
bin | 10011000100011010100… |
… | …110100110000000011000 |
3 | 11122021101211010211112012 |
4 | 103010122212212000120 |
5 | 132432210301200130 |
6 | 2441554503005052 |
7 | 163450133456522 |
oct | 23043246460030 |
9 | 4567354124465 |
10 | 1310411350040 |
11 | 465819054611 |
12 | 191b72139788 |
13 | 9675709b3b0 |
14 | 475d21c8a12 |
15 | 24147e89995 |
hex | 1311a9a6018 |
1310411350040 has 64 divisors (see below), whose sum is σ = 3252672128160. Its totient is φ = 472043105280.
The previous prime is 1310411349953. The next prime is 1310411350043. The reversal of 1310411350040 is 400531140131.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 1310411349988 and 1310411350015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1310411350043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30710654 + ... + 30753293.
Almost surely, 21310411350040 is an apocalyptic number.
1310411350040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1310411350040 is an abundant number, since it is smaller than the sum of its proper divisors (1942260778120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310411350040 is a wasteful number, since it uses less digits than its factorization.
1310411350040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61464012 (or 61464008 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 1310411350040 its reverse (400531140131), we get a palindrome (1710942490171).
The spelling of 1310411350040 in words is "one trillion, three hundred ten billion, four hundred eleven million, three hundred fifty thousand, forty".
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