13104304343240 has 128 divisors (see below), whose sum is σ = 33517134633600. Its totient is φ = 4567300577280.

The previous prime is 13104304343231. The next prime is 13104304343293. The reversal of 13104304343240 is 4234340340131.

It is a junction number, because it is equal to n+sod(n) for n = 13104304343197 and 13104304343206.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1999994 + ... + 5496233.

It is an arithmetic number, because the mean of its divisors is an integer number (261852614325).

Almost surely, 2^{13104304343240} is an apocalyptic number.

13104304343240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13104304343240 is an abundant number, since it is smaller than the sum of its proper divisors (20412830290360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104304343240 is a wasteful number, since it uses less digits than its factorization.

13104304343240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7496415 (or 7496411 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 13104304343240 its reverse (4234340340131), we get a palindrome (17338644683371).

The spelling of 13104304343240 in words is "thirteen trillion, one hundred four billion, three hundred four million, three hundred forty-three thousand, two hundred forty".