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13104344413211 is a prime number
BaseRepresentation
bin1011111010110001011111…
…0010110011010000011011
31201101202121021220221002012
42332230113302303100123
53204200144132210321
643512015215300135
72521520604441542
oct276542762632033
951352537827065
1013104344413211
1141a2580878837
12157786251a64b
1374097156785c
1433437a051159
1517ad19eca05b
hexbeb17cb341b

13104344413211 has 2 divisors, whose sum is σ = 13104344413212. Its totient is φ = 13104344413210.

The previous prime is 13104344413201. The next prime is 13104344413243. The reversal of 13104344413211 is 11231444340131.

It is a happy number.

It is an a-pointer prime, because the next prime (13104344413243) can be obtained adding 13104344413211 to its sum of digits (32).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13104344413211 is a prime.

It is a super-2 number, since 2×131043444132112 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13104344413201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552172206605 + 6552172206606.

It is an arithmetic number, because the mean of its divisors is an integer number (6552172206606).

Almost surely, 213104344413211 is an apocalyptic number.

13104344413211 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104344413211 is an equidigital number, since it uses as much as digits as its factorization.

13104344413211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 32.

Adding to 13104344413211 its reverse (11231444340131), we get a palindrome (24335788753342).

The spelling of 13104344413211 in words is "thirteen trillion, one hundred four billion, three hundred forty-four million, four hundred thirteen thousand, two hundred eleven".