13104422104230 has 24 divisors (see below), whose sum is σ = 34071497471232. Its totient is φ = 3494512561104.

The previous prime is 13104422104229. The next prime is 13104422104261. The reversal of 13104422104230 is 3240122440131.

13104422104230 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 4 + 422 + 1 + 0 + 4 + 230 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 13104422104194 and 13104422104203.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 72802344934 + ... + 72802345113.

It is an arithmetic number, because the mean of its divisors is an integer number (1419645727968).

Almost surely, 2^{13104422104230} is an apocalyptic number.

13104422104230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13104422104230 is an abundant number, since it is smaller than the sum of its proper divisors (20967075367002).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104422104230 is a wasteful number, since it uses less digits than its factorization.

13104422104230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 145604690060 (or 145604690057 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 13104422104230 its reverse (3240122440131), we get a palindrome (16344544544361).

The spelling of 13104422104230 in words is "thirteen trillion, one hundred four billion, four hundred twenty-two million, one hundred four thousand, two hundred thirty".