Base | Representation |
---|---|
bin | 1011111010110001110001… |
… | …1100011101110001100011 |
3 | 1201101202210201202022101021 |
4 | 2332230130130131301203 |
5 | 3204200324121203011 |
6 | 43512031043550311 |
7 | 2521522542624124 |
oct | 276543434356143 |
9 | 51352721668337 |
10 | 13104422444131 |
11 | 41a26109245a7 |
12 | 157788468b397 |
13 | 7409847888b5 |
14 | 33438656404b |
15 | 17ad21c90471 |
hex | beb1c71dc63 |
13104422444131 has 2 divisors, whose sum is σ = 13104422444132. Its totient is φ = 13104422444130.
The previous prime is 13104422444123. The next prime is 13104422444143. The reversal of 13104422444131 is 13144422440131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13104422444131 - 23 = 13104422444123 is a prime.
It is a super-2 number, since 2×131044224441312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13104422444101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552211222065 + 6552211222066.
It is an arithmetic number, because the mean of its divisors is an integer number (6552211222066).
Almost surely, 213104422444131 is an apocalyptic number.
13104422444131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104422444131 is an equidigital number, since it uses as much as digits as its factorization.
13104422444131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36864, while the sum is 34.
Adding to 13104422444131 its reverse (13144422440131), we get a palindrome (26248844884262).
It can be divided in two parts, 1310442 and 2444131, that added together give a palindrome (3754573).
The spelling of 13104422444131 in words is "thirteen trillion, one hundred four billion, four hundred twenty-two million, four hundred forty-four thousand, one hundred thirty-one".
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