Base | Representation |
---|---|
bin | 1011111010110001110001… |
… | …1100011101110001100100 |
3 | 1201101202210201202022101022 |
4 | 2332230130130131301210 |
5 | 3204200324121203012 |
6 | 43512031043550312 |
7 | 2521522542624125 |
oct | 276543434356144 |
9 | 51352721668338 |
10 | 13104422444132 |
11 | 41a26109245a8 |
12 | 157788468b398 |
13 | 7409847888b6 |
14 | 33438656404c |
15 | 17ad21c90472 |
hex | beb1c71dc64 |
13104422444132 has 24 divisors (see below), whose sum is σ = 24202753612800. Its totient is φ = 6191150785056.
The previous prime is 13104422444131. The next prime is 13104422444143. The reversal of 13104422444132 is 23144422440131.
It is a super-2 number, since 2×131044224441322 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13104422444092 and 13104422444101.
It is not an unprimeable number, because it can be changed into a prime (13104422444131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 225070907 + ... + 225129122.
It is an arithmetic number, because the mean of its divisors is an integer number (1008448067200).
Almost surely, 213104422444132 is an apocalyptic number.
It is an amenable number.
13104422444132 is a deficient number, since it is larger than the sum of its proper divisors (11098331168668).
13104422444132 is a wasteful number, since it uses less digits than its factorization.
13104422444132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 450200435 (or 450200433 counting only the distinct ones).
The product of its (nonzero) digits is 73728, while the sum is 35.
Adding to 13104422444132 its reverse (23144422440131), we get a palindrome (36248844884263).
The spelling of 13104422444132 in words is "thirteen trillion, one hundred four billion, four hundred twenty-two million, four hundred forty-four thousand, one hundred thirty-two".
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