131044251002591 has 2 divisors, whose sum is σ = 131044251002592. Its totient is φ = 131044251002590.

The previous prime is 131044251002573. The next prime is 131044251002629. The reversal of 131044251002591 is 195200152440131.

It is an a-pointer prime, because the next prime (131044251002629) can be obtained adding 131044251002591 to its sum of digits (38).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131044251002591 - 2⁴² = 126646204491487 is a prime.

It is a super-3 number, since 3×131044251002591³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131044251092591) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522125501295 + 65522125501296.

It is an arithmetic number, because the mean of its divisors is an integer number (65522125501296).

Almost surely, 2^{131044251002591} is an apocalyptic number.

131044251002591 is a deficient number, since it is larger than the sum of its proper divisors (1).

131044251002591 is an equidigital number, since it uses as much as digits as its factorization.

131044251002591 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 38.

The spelling of 131044251002591 in words is "one hundred thirty-one trillion, forty-four billion, two hundred fifty-one million, two thousand, five hundred ninety-one".