Base | Representation |
---|---|
bin | 10011000100011100100… |
… | …011010000100010110010 |
3 | 11122021111002122011011220 |
4 | 103010130203100202302 |
5 | 132432242132431010 |
6 | 2442002031245510 |
7 | 163451011316664 |
oct | 23043443204262 |
9 | 4567432564156 |
10 | 1310444030130 |
11 | 465835545654 |
12 | 191b81079896 |
13 | 96760aa1221 |
14 | 475d6694534 |
15 | 2414ac92970 |
hex | 1311c8d08b2 |
1310444030130 has 32 divisors (see below), whose sum is σ = 3158920603584. Its totient is φ = 347912304576.
The previous prime is 1310444030111. The next prime is 1310444030143. The reversal of 1310444030130 is 310304440131.
It is a super-3 number, since 3×13104440301303 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 1310444030130.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 96207877 + ... + 96221496.
It is an arithmetic number, because the mean of its divisors is an integer number (98716268862).
Almost surely, 21310444030130 is an apocalyptic number.
1310444030130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1310444030130 is an abundant number, since it is smaller than the sum of its proper divisors (1848476573454).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310444030130 is a wasteful number, since it uses less digits than its factorization.
1310444030130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 192429610.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 1310444030130 its reverse (310304440131), we get a palindrome (1620748470261).
The spelling of 1310444030130 in words is "one trillion, three hundred ten billion, four hundred forty-four million, thirty thousand, one hundred thirty".
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