131044404005440 has 56 divisors (see below), whose sum is σ = 312186292585272. Its totient is φ = 52394781143040.

The previous prime is 131044404005387. The next prime is 131044404005521. The reversal of 131044404005440 is 44500404440131.

It can be written as a sum of positive squares in 4 ways, for example, as 10734744537664 + 120309659467776 = 3276392^2 + 10968576^2 .

It is a super-2 number, since 2×131044404005440² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131044404005396 and 131044404005405.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 89036359 + ... + 90496198.

It is an arithmetic number, because the mean of its divisors is an integer number (5574755224737).

Almost surely, 2^{131044404005440} is an apocalyptic number.

131044404005440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131044404005440 is an abundant number, since it is smaller than the sum of its proper divisors (181141888579832).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131044404005440 is a wasteful number, since it uses less digits than its factorization.

131044404005440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 179534855 (or 179534845 counting only the distinct ones).

The product of its (nonzero) digits is 61440, while the sum is 34.

Adding to 131044404005440 its reverse (44500404440131), we get a palindrome (175544808445571).

The spelling of 131044404005440 in words is "one hundred thirty-one trillion, forty-four billion, four hundred four million, five thousand, four hundred forty".