13104524332040 has 64 divisors (see below), whose sum is σ = 31200484296960. Its totient is φ = 4943286557440.

The previous prime is 13104524331961. The next prime is 13104524332051. The reversal of 13104524332040 is 4023342540131.

It is a junction number, because it is equal to n+sod(n) for n = 13104524331988 and 13104524332006.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 100244879 + ... + 100375518.

It is an arithmetic number, because the mean of its divisors is an integer number (487507567140).

Almost surely, 2^{13104524332040} is an apocalyptic number.

13104524332040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13104524332040 is an abundant number, since it is smaller than the sum of its proper divisors (18095959964920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104524332040 is a wasteful number, since it uses less digits than its factorization.

13104524332040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 200620502 (or 200620498 counting only the distinct ones).

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 13104524332040 its reverse (4023342540131), we get a palindrome (17127866872171).

The spelling of 13104524332040 in words is "thirteen trillion, one hundred four billion, five hundred twenty-four million, three hundred thirty-two thousand, forty".