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1310521251119 is a prime number
BaseRepresentation
bin10011000100100001001…
…001110101010100101111
311122021200110221101110112
4103010201021311110233
5132432421420013434
62442013430330235
7163452636560033
oct23044111652457
94567613841415
101310521251119
11465875098953
12191ba2ab997b
1396773a9a712
1447602a361c3
1524152947dce
hex1312127552f

1310521251119 has 2 divisors, whose sum is σ = 1310521251120. Its totient is φ = 1310521251118.

The previous prime is 1310521250993. The next prime is 1310521251121. The reversal of 1310521251119 is 9111521250131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1310521251119 - 224 = 1310504473903 is a prime.

It is a super-3 number, since 3×13105212511193 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 1310521251121, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310521251199) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655260625559 + 655260625560.

It is an arithmetic number, because the mean of its divisors is an integer number (655260625560).

Almost surely, 21310521251119 is an apocalyptic number.

1310521251119 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310521251119 is an equidigital number, since it uses as much as digits as its factorization.

1310521251119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2700, while the sum is 32.

The spelling of 1310521251119 in words is "one trillion, three hundred ten billion, five hundred twenty-one million, two hundred fifty-one thousand, one hundred nineteen".