Base | Representation |
---|---|
bin | 1011111010110101011011… |
… | …1010001011010101010010 |
3 | 1201101212100002102112101012 |
4 | 2332231112322023111102 |
5 | 3204204331221431232 |
6 | 43512312243210522 |
7 | 2521556053100441 |
oct | 276552672132522 |
9 | 51355302375335 |
10 | 13105403311442 |
11 | 41a2a7456a742 |
12 | 1577ab9076a42 |
13 | 740aaca57360 |
14 | 33443a930d58 |
15 | 17ad7ce429b2 |
hex | beb56e8b552 |
13105403311442 has 32 divisors (see below), whose sum is σ = 21310206926400. Its totient is φ = 6008794429248.
The previous prime is 13105403311439. The next prime is 13105403311453. The reversal of 13105403311442 is 24411330450131.
It is a junction number, because it is equal to n+sod(n) for n = 13105403311399 and 13105403311408.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 273092 + ... + 5126927.
It is an arithmetic number, because the mean of its divisors is an integer number (665943966450).
Almost surely, 213105403311442 is an apocalyptic number.
13105403311442 is a deficient number, since it is larger than the sum of its proper divisors (8204803614958).
13105403311442 is a wasteful number, since it uses less digits than its factorization.
13105403311442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5400650.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 13105403311442 its reverse (24411330450131), we get a palindrome (37516733761573).
The spelling of 13105403311442 in words is "thirteen trillion, one hundred five billion, four hundred three million, three hundred eleven thousand, four hundred forty-two".
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