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13105403311453 is a prime number
BaseRepresentation
bin1011111010110101011011…
…1010001011010101011101
31201101212100002102112101121
42332231112322023111131
53204204331221431303
643512312243210541
72521556053100455
oct276552672132535
951355302375347
1013105403311453
1141a2a7456a752
121577ab9076a51
13740aaca5736b
1433443a930d65
1517ad7ce429bd
hexbeb56e8b55d

13105403311453 has 2 divisors, whose sum is σ = 13105403311454. Its totient is φ = 13105403311452.

The previous prime is 13105403311439. The next prime is 13105403311459. The reversal of 13105403311453 is 35411330450131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13103509495129 + 1893816324 = 3619877^2 + 43518^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13105403311453 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13105403311459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552701655726 + 6552701655727.

It is an arithmetic number, because the mean of its divisors is an integer number (6552701655727).

Almost surely, 213105403311453 is an apocalyptic number.

It is an amenable number.

13105403311453 is a deficient number, since it is larger than the sum of its proper divisors (1).

13105403311453 is an equidigital number, since it uses as much as digits as its factorization.

13105403311453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 34.

Adding to 13105403311453 its reverse (35411330450131), we get a palindrome (48516733761584).

The spelling of 13105403311453 in words is "thirteen trillion, one hundred five billion, four hundred three million, three hundred eleven thousand, four hundred fifty-three".