Base | Representation |
---|---|
bin | 1011111010110101110110… |
… | …0100010110011101000111 |
3 | 1201101212121212122102220021 |
4 | 2332231131210112131013 |
5 | 3204210043321432333 |
6 | 43512331313520011 |
7 | 2521561610511511 |
oct | 276553544263507 |
9 | 51355555572807 |
10 | 13105515030343 |
11 | 41a302163580a |
12 | 1577b2a573007 |
13 | 740ac9c41c08 |
14 | 33444b6d2bb1 |
15 | 17ad87b5e82d |
hex | beb5d916747 |
13105515030343 has 2 divisors, whose sum is σ = 13105515030344. Its totient is φ = 13105515030342.
The previous prime is 13105515030329. The next prime is 13105515030367. The reversal of 13105515030343 is 34303051550131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13105515030343 - 213 = 13105515022151 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13105515030299 and 13105515030308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13105515033343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552757515171 + 6552757515172.
It is an arithmetic number, because the mean of its divisors is an integer number (6552757515172).
Almost surely, 213105515030343 is an apocalyptic number.
13105515030343 is a deficient number, since it is larger than the sum of its proper divisors (1).
13105515030343 is an equidigital number, since it uses as much as digits as its factorization.
13105515030343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40500, while the sum is 34.
Adding to 13105515030343 its reverse (34303051550131), we get a palindrome (47408566580474).
The spelling of 13105515030343 in words is "thirteen trillion, one hundred five billion, five hundred fifteen million, thirty thousand, three hundred forty-three".
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