13110000000103 has 2 divisors, whose sum is σ = 13110000000104. Its totient is φ = 13110000000102.

The previous prime is 13110000000101. The next prime is 13110000000107. The reversal of 13110000000103 is 30100000001131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13110000000103 - 2¹ = 13110000000101 is a prime.

Together with 13110000000101, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 13110000000103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13110000000101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555000000051 + 6555000000052.

It is an arithmetic number, because the mean of its divisors is an integer number (6555000000052).

Almost surely, 2^{13110000000103} is an apocalyptic number.

13110000000103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110000000103 is an equidigital number, since it uses as much as digits as its factorization.

13110000000103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 13110000000103 its reverse (30100000001131), we get a palindrome (43210000001234).

The spelling of 13110000000103 in words is "thirteen trillion, one hundred ten billion, one hundred three", and thus it is an aban number.