13110041213300 has 72 divisors (see below), whose sum is σ = 30122933883840. Its totient is φ = 4935432486400.

The previous prime is 13110041213287. The next prime is 13110041213407. The reversal of 13110041213300 is 331214001131.

It is a super-2 number, since 2×13110041213300² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 145507265 + ... + 145597335.

It is an arithmetic number, because the mean of its divisors is an integer number (418374081720).

Almost surely, 2^{13110041213300} is an apocalyptic number.

13110041213300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13110041213300 is an abundant number, since it is smaller than the sum of its proper divisors (17012892670540).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13110041213300 is a wasteful number, since it uses less digits than its factorization.

13110041213300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 175721 (or 175714 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 13110041213300 its reverse (331214001131), we get a palindrome (13441255214431).

The spelling of 13110041213300 in words is "thirteen trillion, one hundred ten billion, forty-one million, two hundred thirteen thousand, three hundred".