13110100401432 has 64 divisors (see below), whose sum is σ = 33313572437760. Its totient is φ = 4298261673600.

The previous prime is 13110100401427. The next prime is 13110100401499. The reversal of 13110100401432 is 23410400101131.

It is a junction number, because it is equal to n+sod(n) for n = 13110100401399 and 13110100401408.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 55195807 + ... + 55432817.

It is an arithmetic number, because the mean of its divisors is an integer number (520524569340).

Almost surely, 2^{13110100401432} is an apocalyptic number.

13110100401432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13110100401432 is an abundant number, since it is smaller than the sum of its proper divisors (20203472036328).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13110100401432 is a wasteful number, since it uses less digits than its factorization.

13110100401432 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 274864 (or 274860 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 13110100401432 its reverse (23410400101131), we get a palindrome (36520500502563).

The spelling of 13110100401432 in words is "thirteen trillion, one hundred ten billion, one hundred million, four hundred one thousand, four hundred thirty-two".