Base | Representation |
---|---|
bin | 11101110011110001101000… |
… | …110111000101110101101010 |
3 | 122012012011110212102200210200 |
4 | 131303301220313011311222 |
5 | 114140431021244443102 |
6 | 1142455042530053030 |
7 | 36420521305654062 |
oct | 3563615067056552 |
9 | 565164425380720 |
10 | 131101341015402 |
11 | 3885584821aa0a |
12 | 12854399a1a176 |
13 | 581ca5a1291a4 |
14 | 24534a57c23a2 |
15 | 10253a7b3c51c |
hex | 773c68dc5d6a |
131101341015402 has 96 divisors (see below), whose sum is σ = 299312703817920. Its totient is φ = 41357569317120.
The previous prime is 131101341015377. The next prime is 131101341015433. The reversal of 131101341015402 is 204510143101131.
131101341015402 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 0 + 13 + 4 + 101 + 540 + 2 = 666.
131101341015402 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1503050152 + ... + 1503137372.
It is an arithmetic number, because the mean of its divisors is an integer number (3117840664770).
Almost surely, 2131101341015402 is an apocalyptic number.
131101341015402 is an abundant number, since it is smaller than the sum of its proper divisors (168211362802518).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131101341015402 is a wasteful number, since it uses less digits than its factorization.
131101341015402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91748 (or 91745 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 27.
Adding to 131101341015402 its reverse (204510143101131), we get a palindrome (335611484116533).
The spelling of 131101341015402 in words is "one hundred thirty-one trillion, one hundred one billion, three hundred forty-one million, fifteen thousand, four hundred two".
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